POV-Ray: Newsgroups: povray.binaries.images: Megpov: how to do a superelipse? Do we need x^p=sign(x)*|x|^p?: Re: Megpov: how to do a superelipse? Do we need x^p=sign(x)*|x|^p?

POV-Ray : Newsgroups : povray.binaries.images : Megpov: how to do a superelipse? Do we need x^p=sign(x)\|x\|^p? : Re: Megpov: how to do a superelipse? Do we need x^p=sign(x)\|x\|^p?		Server Time 19 Aug 2024 06:20:06 EDT (-0400)

From: Tor Olav Kristensen
Date: 4 Jan 2001 20:02:09
Message: <3A551CB5.7A4B4E1F@online.no>

Chris Huff wrote:
> 
> In article <3A53D643.959D0047@online.no>, Tor Olav Kristensen
> <tor### [at] onlineno> wrote:
> 
> > Maybe it is done like this ?
> >
> > x^n = exp(n*ln(x))
> 
> Uh, I think "x^n = pow(x, n)" is more likely...

Yes, but do you know how this is actually computed ?


Regards,

Tor Olav
-- 
mailto:tor### [at] hotmailcom
http://www.crosswinds.net/~tok/tokrays.html

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